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A physics professor is trying to flee a class of angry students by falling onto a moving freight train from the Howard and 26th St overpass. The train is y = −5 m below the overpass. It is moving at a velocity of v = 10 m/s. Taking the acceleration due to gravity to be g = −10 m/s^2, how far away should the train be before the professor falls from the overpass (and escapes the wrath of the students)?

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jorgezarate

Answer:

The train should be a 10 meters away before the professor falls

Explanation:

Calculation of the teacher's fall time:

[tex]y(t)=v_{o}t-1/2*g*t^{2}[/tex]

in this case Vo=0 and y=-5:

[tex]-5=-1/2*10*t^{2}[/tex]

[tex]t=1s[/tex]

Calculation how far away is the train when the professor falls:

The distance the train travel while the professor is falling:

[tex]d=v_{train}*t=10m/s*1s=10m[/tex]

So the train should be a 10 meters away before the professor falls

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