Answer:
t = 1.084 s
s = 8.25 m
Explanation:
given,
height from where skate board start (h) = 1 m
speed = 7.6 m/s
we know
v² = u² + 2 g h
v² =7.6² + 2×9.81× 1
v = 8.79 m/s
[tex]v_y = v sin \theta[/tex]
[tex]v_y =8.79\times sin 30^0[/tex]
[tex]v_y = 4.39 m/s[/tex]
[tex]s = s_o + v_y \times t +\dfrac{1}{2}at^2[/tex]
[tex]0 = 1 + 4.39 \times t - 4.9 t^2[/tex]
t = 1.084 s
then horizontal distance
[tex]s =v_x \times t[/tex]
[tex]s = 8.79 \times cos 30^0 \times 1.084[/tex]
s = 8.25 m
