Let P(x) be the statement"x= x2", If the domain consists of the integers, what are these truth values? (a) P(0) (b) P(1) (c) P(2) (d) P(-1) (e)

Answer: i guess the problem is with P(x) => "x = [tex]x^{2}[/tex]", then P(x) is true if that equality is true, and is false if the equality is false.

so lets see case for case.

a) x = 0, and [tex]0^{2}[/tex] = 0. So p(0) is true.

b) x = 1 and [tex]1^{2}[/tex] = 1, so P(1) is true.

c) x = 2, and [tex]2^{2}[/tex] = 4, and 2 ≠ 4, then P(2) is false.

d) x= -1 and [tex]1^{2}[/tex] = 1, and 1 ≠ -1, so P(-1) is false.

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MrRoyal MrRoyal · Answer 2 · 2022-03-25T13:29:27+01:00

The truth value of P(0) and P(1) is true while the truth value of P(2) and P(-1) is false

The statement is given as:

[tex]x = x^2[/tex]

For P(0), we have:

[tex]0 = 0^2[/tex]

[tex]0 = 0[/tex] --- this is true

For P(1), we have:

[tex]1 = 1^2[/tex]

[tex]1 = 1[/tex] --this is true

For P(2), we have:

[tex]2 = 2^2[/tex]

[tex]2= 4[/tex] -- this is false

For P(-1), we have:

[tex](-1) = (-1)^2[/tex]

[tex](-1) = 1[/tex] --- this is false

Hence, the truth value of P(0) and P(1) is true while the truth value of P(2) and P(-1) is false