Answer:
The distance between the 2 points is 4.6558 meters.
Explanation:
The distance between 2 points [tex](r_1,\theta _1),(r_2,\theta _2)[/tex] is given by
[tex]d=\sqrt{r_{1}^{2}+r_{2}^{2}-2r_1\cdot r_2cos(\theta _2-\theta _1)}[/tex]
In our case the given 2 points are [tex](2.60,50.0^{o}),(3.60,-46.0^{o})[/tex] hence the distance is
[tex]d=\sqrt{2.60^{2}+3.60^{2}-2\cdot 2.60\cdot 3.60\cdot cos(-46.0-50)}\\\\\therefore d=4.6558m[/tex]
