Answer:
Energy density will be 14.73 [tex]J/m^3[/tex]
Explanation:
We have given capacitance [tex]C=225\mu F=225\times 10^{-6}F[/tex]
Potential difference between the plates = 365 V
Plate separation d = 0.200 mm [tex]0.2\times 10^{-3}m[/tex]
We know that there is relation between electric field and potential
[tex]E=\frac{V}{d}[/tex], here E is electric field, V is potential and d is separation between the plates
So [tex]E=\frac{V}{d}=\frac{365}{0.2\times 10^{-3}}=1825000N/C[/tex]
Energy density is given by [tex]E=\frac{1}{2}\varepsilon _0E^2=\frac{1}{2}\times 8.85\times 10^{-12}\times (1.825\times 10^6)^2=14.73J/m^3[/tex]
