Answer:
[tex]y_{max}=11m[/tex]
Explanation:
The maximum vertical displacement that the ball reaches can be calculate using the following formula:
[tex]v^{2}=v^{2} _{o}+2g(y-y_{o})[/tex]
At the highest point, its velocity becomes 0 because it stop going up and starts going down.
[tex]0=(29.4sin(30))^{2} -2(9.8)y[/tex]
Solving for y
[tex]y=\frac{(29.4sin(30))^{2}}{2(9.8)} =11m[/tex]
