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You drive a car 690 ft to the east, then 380 ft to the north. a) What is the magnitude of your displacement?
b) What is the direction of your displacement?

Respuesta :

Answer:displacement =787.71 m

Explanation:

Given

Driver driver the car 690 ft to the east

then turn 380 ft to the north

(a)magnitude of acceleration is [tex]=\sqrt{380^2+690^2}=\sqrt{620500}[/tex]

displacement=787.71 m

(b)direction of displacement

[tex]tan\theta =\frac{380}{690}=0.5507[/tex]

[tex]\theta =28.84^{\circ}[/tex] with east direction

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