Answer:(a)0,(b)1.061 kg-m/s
Explanation:
Given
mass of ball is 0.10 kg
Initial speed is 15 m/s
Maximum height reached by ball is h
[tex]v^2-u^2=2as[/tex]
final velocity =0
[tex]-\left ( 15\right )^2=-2\times 9.81\times s[/tex]
[tex]s=\frac{15^2}{2\times 9.81}=11.467 m[/tex]
thus momentum of ball at maximum height is 0 as velocity is zero
For halfway to maximum height
[tex]v^2-u^2=2as_0[/tex]
where [tex]s_0=\frac{11.467}{2}[/tex]
[tex]s_0=5.73 m[/tex]
[tex]v^2=15^2-2\times 9.81\times 5.73[/tex]
v=10.61 m/s
Thus its momentum is
[tex]mv=0.10\times 10.61=1.061 kg-m/s[/tex]
