Answer:[tex]=\frac{8.014}{4.5}=1.78 m/s^2[/tex]
Explanation:
Given
mass of block(m)=4.5 kg
Horizontal force([tex] F_h[/tex])=3.7 N
another force F at angle of [tex]43^{\circ}[/tex]
if F is pulling Block then
Net Normal reaction=mg-Fsin43=40.12 N
Net Force in Horizontal direction =3.7+Fcos43
=3.7+4.31=8.014 N
thus Net acceleration is a[tex]=\frac{8.014}{4.5}=1.78 m/s^2[/tex]
