Answer:
(a). The time is 26.67 sec.
(b). The distance traveled during this period is 1066.9 m.
Explanation:
Given that,
Speed = 80 m/s
Acceleration = 3 m/s
Initial velocity = 0
(a). We need to calculate the time
Using equation of motion
[tex]v = u+at[/tex]
[tex]t = \dfrac{v-u}{a}[/tex]
Put the value into the formula
[tex]t = \dfrac{80-0}{3}[/tex]
[tex]t =26.67\ sec[/tex]
The time is 26.67 sec.
(b). We need to calculate the distance traveled during this period
Using equation of motion
[tex]s = ut+\dfrac{1}{2}at^2[/tex]
[tex]s = 0+\dfrac{1}{2}\times3\times(26.67)^2[/tex]
[tex]s =1066.9\ m[/tex]
The distance traveled during this period is 1066.9 m.
Hence, This is the required solution.
