Answer:
[tex]\Delta \lambda=4.94\times 10^{-13}\ m[/tex]
Explanation:
It is given that,
X-rays are scattered from a target at an angle of, [tex]\theta=37.2^{\circ}[/tex]
We need to find the wavelength shift of the scattered x-rays. The shift in wavelength is given by :
[tex]\Delta \lambda=\dfrac{h}{mc}(1-cos\ \theta)[/tex]
h is the Planck's constant
m is the mass of electron
c is the speed of light
[tex]\Delta \lambda=\dfrac{6.63\times 10^{-34}}{9.1\times 10^{-31}\times 3\times 10^8}(1-cos(37.2))[/tex]
[tex]\Delta \lambda=4.94\times 10^{-13}\ m[/tex]
So, the wavelength shift of the scattered x- rays is [tex]4.94\times 10^{-13}\ m[/tex]. Hence, this is the required solution.
