Answer:
[tex]\lambda=8.006\times 10^{-11}\ m[/tex]
Explanation:
Given that,
The speed of an electron, [tex]v=9.1\times 10^6\ m/s[/tex]
We need to find the wavelength of this electron. It can be calculated using De -broglie wavelength concept as :
[tex]\lambda=\dfrac{h}{mv}[/tex]
h is the Planck's constant
[tex]\lambda=\dfrac{6.63\times 10^{-34}}{9.1\times 10^{-31}\times 9.1\times 10^6}[/tex]
[tex]\lambda=8.006\times 10^{-11}\ m[/tex]
So, the wavelength of the electron is [tex]8.006\times 10^{-11}\ m[/tex]. Hence, this is the required solution.
