An exam has 10 problems. How many ways can (integer points be assigned to the problems if the total of the points is 100 and each problem is worth at least 5 points?

Respuesta :

Answer:

number of way is [tex]\frac{59!}{50)!9!}[/tex]

Step-by-step explanation:

given data:

total number of problems 100

total points for each problem 5

let ten problems are

[tex]x_1, x_2,........., x_{10}[/tex]

according to the given information

[tex]x_1 +x_2 +.......+x_{10} = 100[/tex]

[tex]x_i \geq 5[/tex]

where i =1 + 10

so, number of way integer point can assign are

   [tex]^{(n+r-1)}C_{(r-1)}[/tex]

where

r = 10

[tex]n = 100 - 10\times 5 = 50[/tex]

so, we have

[tex]^{(59)}C_{9}[/tex]

[tex]\frac{59!}{59-9)!9!}[/tex]

number of way is [tex]\frac{59!}{50)!9!}[/tex]