Answer:
Force between two spheres will be 14400 N
And as the both charges of opposite nature so force will be attractive
Explanation:
We have given two conducting spheres of charges [tex]q_1=-20\mu C=-20\times 10^{-6}C\ and\ q_2=50\mu C=50\times 10^{-6}C[/tex]
Distance between the spheres = 2.5 cm =0.025 m
According to coulombs law we know that force between two charges is given by [tex]F=\frac{1}{4\pi \varepsilon _0}\frac{q_1q_2}{r^2}=\frac{Kq_1q_2}{r^2}=\frac{9\times 10^9\times 20\times 10^{-6}\times 50\times 10^{-6}}{0.025^2}=14400N[/tex]
As the both charges of opposite nature so force will be attractive
