Answer:
The mass of the water on earth is [tex]5.4537\times10^{20}\ kg[/tex]
Explanation:
Given that,
Average depth h= 0.95 mi
[tex]h=0.95\times1.609[/tex]
[tex]h =1.528\ km[/tex]
[tex]h=1.528\times10^{3}\ m[/tex]
Radius of earth [tex]r= 6.37\times10^{6}\ m[/tex]
Density = 1000 kg/m³
We need to calculate the area of surface
Using formula of area
[tex]A =4\pi r^2[/tex]
Put the value into the formula
[tex]A=4\pi\times(6.37\times10^{6})^2[/tex]
[tex]A=5.099\times10^{14}\ m^2[/tex]
We need to calculate the volume of earth
[tex]V = Area\times height[/tex]
Put the value into the formula
[tex]V=5.099\times10^{14}\times1.528\times10^{3}[/tex]
[tex]V=7.791\times10^{17}\ m^3[/tex]
Now, 70 % volume of the total volume
[tex]V= 7.791\times10^{17}\times\dfrac{70}{100}[/tex]
[tex]V=5.4537\times10^{17}\ m^3[/tex]
We need to calculate the mass of the water on earth
Using formula of density
[tex]\rho = \dfrac{m}{V}[/tex]
[tex]m = \rho\times V[/tex]
Put the value into the formula
[tex]m=1000\times5.4537\times10^{17}[/tex]
[tex]m =5.4537\times10^{20}\ kg[/tex]
Hence, The mass of the water on earth is [tex]5.4537\times10^{20}\ kg[/tex]
