Answer:
The column compressed is 57.142 Pa.
Explanation:
Given that,
Height = 3.50 m
Diameter = 50.0 cm
Radius = 25.0 cm
Load [tex]F=5.00\times10^{5}\ kg[/tex]
We need to calculate the column compressed
Using formula of compressed
[tex]P = \dfrac{F}{A}[/tex]
[tex]P=\dfrac{F}{l\times r}[/tex]
Where, F = load
l = length
r = radius
Put the value into the formula
[tex]P=\dfrac{5.00\times10^{5}}{3.50\times25\times10^{2}}[/tex]
[tex]P=57.142\ Pa[/tex]
Hence, The column compressed is 57.142 Pa.