Answer:
The magnitude of charge is 7.15 nC.
Explanation:
Given that,
Electric field = 4.70 N/C
Distance = 3.70 m
We need to calculate the magnitude of charge
Using formula of electric field
[tex]E=\dfrac{kq}{r^2}[/tex]
[tex]q = \dfrac{Er^2}{k}[/tex]
Where, k = Boltzmann constant
r = distance
q = charge
E = electric field
Put the value into the formula
[tex]q =\dfrac{4.70\times(3.70)^2}{9\times10^{9}}[/tex]
[tex]q=7.15\times10^{-9}\ C[/tex]
[tex]q = 7.15\ nC[/tex]
Hence, The magnitude of charge is 7.15 nC.
