Answer:
V=33.66 m/s
[tex]Re=448.8\times 10^6[/tex]
Re>4000, The flow is turbulent flow.
Explanation:
Given that
Pressure difference = 50 mm of Hg
We know that density of Hg=136000[tex]Kg/m^3[/tex]
ΔP= 13.6 x 1000 x 0.05 Pa
ΔP=680 Pa
Diameter of tunnel = 200 mm
Property of air at 25°C
ρ=1.2[tex]Kg/m^3[/tex]
Dynamic viscosity
[tex]\mu =1.8\times 10^{-8}\ Pa.s[/tex]
Velocity of fluid given as
[tex]V=\sqrt{\dfrac{2\Delta P}{\rho_{air}}}[/tex]
[tex]V=\sqrt{\dfrac{2\times 680}{1.2}}[/tex]
V=33.66 m/s
Reynolds number
[tex]Re=\dfrac{\rho _{air}Vd}{\mu }[/tex]
[tex]Re=\dfrac{1.2\times 33.66\times 0.2}{1.8\times 10^{-8}}[/tex]
[tex]Re=448.8\times 10^6[/tex]
Re>4000,So the flow is turbulent flow.
