Answer:
[tex]x=1.75m[/tex]
Explanation:
From the exercise we have that
[tex]y_{o}=1.3m\\v_{o}=3m/s, \beta  =37\\[/tex]
To find how far from the edge of the piano does the cat strike the floor, we need to calculate its time first
[tex]y=y_{o}+v_{oy}t+\frac{1}{2}gt^{2}[/tex]
At the end of the motion y=0m
[tex]0=1.3+3sin(37)t-\frac{1}{2}(9.8)t^{2}[/tex]
Solving for t
[tex]t=-0.36 s[/tex] or [tex]t=0.73s[/tex]
Since the time can't be negative the answer is t=0.73
Knowing that we can calculate how far does the cat strike the floor
[tex]x=v_{ox}t=3cos(37)(0.73)=1.75m[/tex]
