Answer:
Magnitude of electric field on Earth = Q = 6.8 × 10⁵ C
Explanation:
Electric field = E = 150 N/C
Distance from the center of the earth to the surface = Radius of the earth
Radius of the earth = R = 6.38× 10⁶ m
E = k Q / R² is the basic formula for the electric field. k = 9 × 10⁹ N m²/C²
150 = (9 × 10⁹)(Q) / (6.38× 10⁶ )²
⇒ Charge = Q = (150)(6.38× 10⁶ )²/(9 × 10⁹)
= 6.8 × 10⁵ C(2 significant figures).
Answer:
The charge of earth is[tex]-6.8\times 10^{5}Columbs[/tex]
Explanation:
Assuming earth as a spherical body we have
For a sphere of radius 'r' and charge 'q' the electric field generated at a distance 'r' form the center of sphere is given by the equation
[tex]E=\frac{1}{4\pi \epsilon _o }\cdot \frac{Q}{r^{2}}[/tex]
where
'Q' is the total charge on sphere
Now at a distance 'r' equal to radius of earth(6371 km) we have the electric field strength is 150N/C
Using the given values we obtain
[tex]150=\frac{1}{4\pi \epsilon _o}\frac{Q}{(6371\times 10^{3})^2}\\\\\therefore Q=150\times (6371\times 10^{3})^{2}\times 4\pi \epsilon _o\\\\\therefore Q=6.8\times 10^{5}Columbs[/tex]
Now since the electric field is inwards thus we conclude that this charge is negative in magnitude.
