Answer:
Explanation:
Given:
Length of each side of the cube, [tex]L=10\ cm[/tex]
The Elecric flux through one of the side of the cube is, [tex]\phi =-1 kNm^2/C.[/tex]
The net flux through a closed surface is defined as the total charge that lie inside the closed surface divided by [tex]\epsilon_0[/tex]
Since Flux is a scalar quantity. It can added to get total flux through the surface.
[tex]\phi_{total}=\dfrac{Q_{in}}{\epsilon_0}\\6\times {-1}\times 10^3=\dfrac{Q_{in}}{\epsilon_0}\\\\Q_{in}=-6}\times 10^3\epsilon_0\\Q_{in}=-6}\times 10^3\times8.85\times 10^{-12}\\Q_{in}=-53.1\times10^{-9}\ C[/tex]
So the the charge at the centre is calculated.
