The lodhl diner offers a meal combination consisting of an appetizer, a soup, a main course, and a dessert. There are five appetizers, five soups, four main courses, and five desserts. Your diet restricts you to choosing between a dessert and an appetizer. (You cannot have both.) Given this restriction, how many three-course meals are possible?

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JeanaShupp JeanaShupp · Answer 1 · 2019-09-20T16:47:46+02:00

Answer: 100

Step-by-step explanation:

Given : The lodhl diner offers a meal combination consisting of an appetizer, a soup, a main course, and a dessert.

There are 5 appetizers, 5 soups, 4 main courses, and 5 desserts.

Also, a dessert and a appetizer are not allowed to take together.

By Fundamental counting principal ,

Number of three-course meals with dessert and without appetizer :

[tex]5\times4\times5=100[/tex] (1)

Number of three-course meals with appetizer and without dessert :

[tex]5\times5\times4=100[/tex] (2)

Now, the number of meals with either dessert or appetizer :-

[tex]100+100=200[/tex] [Add (1) and (2)]

kalear81840 kalear81840 · Answer 2 · 2022-02-11T03:46:29+01:00

Answer:

500

Step-by-step explanation:

5x5x4x5

we do

5x5=25

25x4=100

100x5= 500

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