Answer
Work done will be [tex]14.7\times 10^{-6}J[/tex] and it will be positive
Explanation:
We have given charge [tex]2.1\times 10^{-6}C[/tex]
We have to find work done in moving the charge from 15 volt to 8 volt
Let [tex]V_1=15V\ and\ V_2=8volt[/tex]
So potential difference [tex]V=V_1-V_2=15-8=7volt[/tex]
We know that work done [tex]W=QV[/tex], here Q is charge and V is potential difference
So work done [tex]W=QV=2.1\times 10^{-6}\times 7=14.7\times 10^{-6}J[/tex]
It will be positive work done because work is done in moving charge from higher potential to lower potential
