Answer:
The flux through one face of a cube is [tex]- 5.2730\times 10^{4} Wb[/tex]
Given:
Charge, Q = [tex]- 2.80\micro C = -2.80\times 10^{- 6} C[/tex]
Solution:
The electric flux, [tex]\phi_{E} = \frac{Q}{\epsilon_{o}}[/tex]
Since, there are 6 faces in a cube, the flux through one face:
[tex]\phi_{E} = \frac{Q}{6\epsilon_{o}}[/tex]
[tex]\phi_{E} = \frac{-2.80\times 10^{- 6}}{6\epsilon_{o}}[/tex]
[tex]\phi_{E} = - 5.2730\times 10^{4} Wb[/tex]
