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Derive the following conversion factors: (a) Convert a viscosity of 1 m^2/s to ft^2/s. (b) Convert a power of 100 W to horsepower. (c) Convert a specific energy of 1 kJ/kg to Btu/lbm.

Respuesta :

Answer:

(a) 10.76 [tex]ft^2/sec[/tex]

(b) 0.134 lbm

(c) 0.4308 Btu/lbm

Explanation:

We have to do conversion

(a) conversion of viscosity [tex]1m^2/sec\ to\  ft^2/sec[/tex]

We know that [tex]1m^2=10.76feet^2[/tex]

So [tex]1m^2/sec=10.76ft^2/sec[/tex]

(b) We have to convert power 100 W in hp

We know that 1 W = 0.00134 hp

So 100 W = 100×0.00134=0.134 hp

(c) We have to convert 1 KJ/kg to Btu/lbm

We know that 1 KJ = 0.94780 Btu

And 1 kg = 2.20 lbm

So [tex]1KJ/kg=\frac{0.9478Btu}{2.20lbm}=0.4308Btu/lbm[/tex]

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