Answer:
4.29%
Explanation:
Given:
Density of water, ρ = 1000 kg/m³
elevation change of Δz = 800 m
work per unit mass delivered, Wp = 8,200 J/kg
Now,
The percent irreversibility = [tex](1-n_p)\times100[/tex]
where,
[tex]n_p\frac{W_{actual}}{W_{theoretical}}[/tex]
also,
[tex]W_{actual}=\frac{g\Delta z}{1000}[/tex]
Where, g is the acceleration due to the gravity
on substituting the values, we get
[tex]W_{actual}=\frac{9.81\times800}{1000}[/tex]
or
[tex]W_{actual}=7.848\ KJ/kg[/tex]
or
[tex]W_{actual}=7848\ J/kg[/tex]
Therefore,
The percent irreversibility = [tex](1-n_p)\times100[/tex]
on substituting the values, we get
The percent irreversibility = [tex](1-\frac{7848}{8,200})\times100[/tex]
or
The percent irreversibility = 4.29%
