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A town has a 1-million-gallon storage capacity water tower. If the density of water is 62.41b/ft and local acceleration due to gravity is 32.1 ft/s, what is the force in lbf the structural base must provide to support the water in the tower?

Respuesta :

Answer:

[tex]w = 8.316\times 10^6 lb[/tex]

Explanation:

force that structural base must be provided with is equal to the weight of water

we know that

[tex]\rho =\frac{mass}{V}[/tex]

[tex]m =\rho V[/tex]

We know that

w = mg

so we have

[tex]w = \rho Vg[/tex]

density of water  is 62.4 lb/ft^3

V = 1 milllion = 100,000 gallons

[tex]g = 32.1 ft/s^2[/tex]

[tex]w = 62.4[\times10^6 gallons \frac{0.134}{1 gallon}] [32.1 ft/s^2 \frac{0.3048 m/s^2}{ft/s^2} \frac{m/s^2}{9.8 m/s^2}][/tex]

[tex]w = 8.316\times 10^6 lb[/tex]

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