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To compute the energy used by a motor, multiply the power that it draws by the time of operation. Con- sider a motor that draws 12.5 hp for 16 h/day, five days per week. Compute the energy used by the mo- tor for one year. Express the result in ft.lb and W.h

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fabianb4235

Answer:

E=52000Hp.h

E=38724920Wh

E=1.028x10^11 ftlb

Explanation:

To solve this problem you must multiply the engine power by the time factor expressed in h / year, to find this value you must perform the conventional unit conversion procedure.

Finally, when you have the result Hp h / year you convert it to Ftlb and Wh

[tex]E=(12.5hp)(\frac{16h}{day} )(\frac{5 days}{week} )(\frac{52week}{year} )\\[/tex]

E=52000Hp.h

[tex]E=52000Hp.h(\frac{744.71Wh}{Hp.h} )\\[/tex]

E=38724920Wh

[tex]E=52000Hph(\frac{1977378.4  ft lb}{1Hph}[/tex]

E=1.028x10^11 ftlb

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