Use Newton's law of universal gravitation to calculate the weight of a 90 kg person standing on the surface of the earth to the nearest 1 N.

Respuesta :

Answer:

W=884 N

Explanation:

Hello, I think I can help you with this

the law of universal gravitation predicts that the force exerted between two bodies of masses and separated by a distance is equal to the product of their masses and inversely proportional to the square of the distance, that is:it is given by

[tex]F=G \frac{m_{1} *m_{2} }{r^{2}} \\\\[/tex]

where

G is  is the universal gravitation constant.

[tex]G=6.67384 *10^{-11}\frac{Nm^{2} }{kg^{2}} \\[/tex]

m1 and m2 are the masses of the objects

and r is the distance between the objects

Step 1

to solve this you are going to need the mass of the earth, and the radius of the earth(average)

Radius of the earth=6371 km=6371000 m

mass of the earth=[tex]5.972 *10^{24}\ Kg\\[/tex]

Let

m1=90 kg

m2=[tex]5.972 *10^{24}\ Kg\\[/tex]

r=6371 km

[tex]G=6.67384 *10^{-11}\frac{Nm^{2} }{kg^{2}}[/tex]

just put the values in the equation

[tex]F=G \frac{m_{1} *m_{2} }{r^{2}}\\F=6.67384 *10^{-11}\frac{Nm^{2} }{kg^{2} }  \frac{90 kg*5.972 *10^{24}\ Kg}{(6371 000m)^{2} }\\F=\frac{3.58*10^{16} N}{4.058*10^{13} } \\F=884 N\\[/tex]

Have a good day.