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Air flows at 45m/s through a right angle pipe bend with a constant diameter of 2cm. What is the overall force required to keep the pipe bend in place? Is it: a) 0.76 N b) 1.08 N c) 1.52 N d) 0.25 N e) 2.56 N

Respuesta :

Answer:

b)1.08 N

Explanation:

Given that

velocity of air V= 45 m/s

Diameter of pipe = 2 cm

Force exerted by fluid  F

[tex]F=\rho AV^2[/tex]

So force exerted in x-direction

[tex]F_x=\rho AV^2[/tex]

[tex]F_x=1.2\times \dfrac{\pi}{4}\times 0.02^2\times 45^2[/tex]

F=0.763 N

So force exerted in y-direction

[tex]F_y=\rho AV^2[/tex]

[tex]F_y=1.2\times \dfrac{\pi}{4}\times 0.02^2\times 45^2[/tex]

F=0.763 N

So the resultant force R

[tex]R=\sqrt{F_x^2+F_y^2}[/tex]

[tex]R=\sqrt{0.763^2+0.763^2}[/tex]

R=1.079

So the force required to hold the pipe is 1.08 N.

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