contestada

Which equations represent the line that is perpendicular to the line 5x - 2y = -6 and passes through the point
(5, -4)? Select three options.
y=-2 X-2
2x +hoy = -10
L2x - 5y = -10
y+ 4 = _{(x - 5)
y- 4 = 5(x+5)

Respuesta :

kudzordzifrancis

Answer

See below

Step-by-step explanation:

The given line has equation

[tex]5x - 2y =  - 6[/tex]

The slope intercept form is

[tex]y =  \frac{5}{2} x + 3[/tex]

The slope of this line is

[tex] m = \frac{5}{2} [/tex]

The line perpendicular to this line has slope

[tex] -  \frac{2}{5} [/tex]

If this line passes through (5,-4), the point-slope form is

[tex]y + 4 =  -  \frac{2}{5} (x  - 5)[/tex]

The slope-intercept form is

[tex]y =  -  \frac{2}{5} x- 2[/tex]

The standard form is

2x+5y=-10

Otras preguntas