Answer:
froce by 6 gallon liquid on moon surface is 2.86 lbf
Explanation:
given data:
at earth surface
volume of an incompressible liquid = Ve = 25 gallons
force by liquid = 70 lbf
on moon
volume of liquid = Vm = 6 gallons
gravitational acceleration on moon is am = 5.51 ft/s2
Due to incompressibility , the density remain constant.
mass of liquid on surface of earth[tex]= \frac{ force}{ acceleration}[/tex]
[tex]mass = \frac{70lbf}{32.2 ft/s2}[/tex]
mass = 2.173 pound
[tex]density \rho = \frac{mass}{volume}[/tex]
[tex]= \frac{2.173}{25} = 0.0869 pound/ gallon[/tex]
froce by 6 gallon liquid on moon surface is
Fm = mass * acceleration
= density* volume * am
= 0.0869 *6* 5.51
= 2.86 lbf
