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A mixture of gases is analyzed and found to have the following volume composition: CO2 12.0%, CO 6.0, CH4 27.3, H2 9.9, and N2 44.8. How much will 38 [mol] of this mixture weigh, in [kg]?

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luchoprat

Answer:

Weight = 0.915 [kg]

Explanation:

When you have a mixture of gases

volumen composition = mol composition

With mol composition you calculate the molar mass of the mixture

CO2 : 44

CO: 28

CH4: 16

H2: 2

N2: 28

MM of Gas Mixture = 44*0.12+28*0.06+16*0.273+2*0.099+28*0.448 = 24.07

(Each molar mass * respective mol fraction)

[tex]Moles = \frac{Weight}{Molar Mass} \\Weight =(Molar Mass)*(Moles)[/tex]

Weight = 38 [mol] * 24.07 [g/mol] = 914.66 [g] = 0.915 [kg]

* Remember the unit of molar mass is: g/mol or kg/kmol or ton/mol-ton, etc

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