Two cars leave a city heading in the same direction. After 3 hours, the faster card is 9 miles ahead of the slower car. The slower car has traveled 153 miles. Find the speed of the two cars.

Respuesta :

Answer:

The speed of the slower car is: 51 miles/hour and the speed of the faster car is 54 miles/hour.

Step-by-step explanation:

First, we can easily find the speed of the slower car, since we know that the speed is given by the formula v=d/t, where d stands for the traveled distance and t for the elapsed time.

[tex]v_{s}=\frac{d_{s}}{t}=\frac{153\ miles}{3\ hours} = 51\ miles/hour[/tex]

Next, for the faster car, we know that the distance traveled is 153+9 miles in the same time, therefore, its speed is given by:

[tex]v_{f}=\frac{d_{f}}{t}=\frac{153+9\ miles}{3\ hours} = 54\ miles/hour[/tex]