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A pharmacist weighed 475 mg of a substance on a balance of dubious accuracy. When checked on a balance of high accuracy, the weight was found to be 445 mg. Calculate the percentage error in the first weighing.

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JeanaShupp

Answer: 6.416%

Step-by-step explanation:

The percentage error formula is given by :-

[tex]\%\text{error}=\dfrac{|\text{Estimate-Actual}|}{\text{Actual}}\times100[/tex]

Given : The estimated weight of a substance = 475 mg

The actual weight of the substance = 445 mg

Then,

[tex]\%\text{error}=\dfrac{| 475-445|}{445}\times100\\\\=\dfrac{30}{445}\times100=6.74157303371\approx6.416\%[/tex]

Hence, the percentage error in the first weighing. = 6.416%

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