Respuesta :
Answer:
angle of elevation will be [tex]2.14^o.[/tex]
Step-by-step explanation:
Given,
height of tower = 150 ft
height of tower = 1200 ft
So, total height of peak of tower = 1200 + 150
= 1350 ft
distance of user from cell tower = 5 miles
= 5 x 5280 feet
= 26,400 feet
Since the height of user from sea level = 400 ft
so, height of peak of tower with respect to user = 1350 - 400 ft
= 950 ft
If the angle of depression is assumed as [tex]\theta[/tex], then we can write
[tex]tan\theta\ =\ \dfrac{\textrm{height of peak of tower w.r.t user}}{\textrm{distance of user from tower}}[/tex]
[tex]=>\ tan\theta\ =\ \dfrac{950}{26400}[/tex]
[tex]=>\ tan\theta\ =\ 0.374[/tex]
[tex]=>\ \theta\ =\ 2.14^o[/tex]
So, the angle of elevation will be [tex]2.14^o.[/tex]
