Answer:
overflow rate 20.53 m^3/d/m^2
Detention time 2.34 hr
weir loading 114.06 m^3/d/m
Explanation:
calculation for single clarifier
[tex]sewag\ flow Q = \frac{12900}{2} = 6450 m^2/d[/tex]
[tex]surface\ area =\frac{pi}{4}\times diameter ^2 = \frac{pi}{4}\times 20^2[/tex]
[tex]surface area = 314.16 m^2[/tex]
volume of tank[tex] V = A\times side\ water\ depth[/tex]
[tex]=314.16\times 2 = 628.32m^3[/tex]
[tex]Length\ of\ weir = \pi \times diameter of weir[/tex]
[tex] = \pi \times 18 = 56.549 m[/tex]
overflow rate =[tex] v_o = \frac{flow}{surface\ area} = \frac{6450}{314.16} = 20.53 m^3/d/m^2[/tex]
Detention time[tex] t_d = \frac{volume}{flow} = \frac{628.32}{6450} \times 24 = 2.34 hr[/tex]
weir loading[tex]= \frac{flow}{weir\ length} = \frac{6450}{56.549} = 114.06 m^3/d/m[/tex]
