Answer:
60m (to nearest meter)
Explanation: How far the ball traveled refers to the range covered by the ball before it hits the ground. For an object projected at an angle of ∝ to the horizontal, the range, R covered is given by;
[tex]R=u^{2}sin2\alpha/2g[/tex]
Where u is the initial velocity and g is acceleration due to gravity.
[tex]u=26mls\\\alpha=30^{o}\\g=9.81m/s^{2}[/tex]
The value of g could be safely assumed to be [tex]9.8m/s^{2}[/tex]
Therefore;
[tex]R=26^{2}sin2(30)/9.8[/tex]
[tex]R=(26*26*sin60)/9.8[/tex]
[tex]R=676*0.8660/9.8[/tex]
[tex]R=59.68m[/tex] which is approximately 60m to nearest meter.
