con1fuselila
contestada

how many real number solutions does the equation have?-8x^2-8x-2=0
1
2
no solutions
or
infinitely many solutions

solve the equation by completing the square. round to the nearest hundredth. x^2+6x=-7
4.41,1.59
-4.41,1.59
-4.41,-1.59
4.41,-1.59

and the last one is
solve the systems of equations algebraically. show all of your steps.
y=x^2+2x
y=3x+20

Respuesta :

caylus
Hello,

I)
1 solution with multiplicity 2
(2x+1)²=0

II) ANSWER C (-4.41, -1.59)
-3-√2 and -3+√2

III)
y=x²+2x
y=3x+20
==>x²+2x=3x+20
==>x²-x-20=

Δ=1+4*20=81=9²

(x=(1-9)/2=-4 and y= 3*(-4)+20=8 ) or (x=(1+9)/2=5 and y=3*5+20=35)


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