Veronika’s five test scores are 59, 80, 95, 88, and 93. If the outlier of 59 is removed, what is the mean absolute deviation of the remaining four test scores?
4.5
5
10.8
36

Step-by-step explanation: Your answer is found by calculating the mean of 59, 80, 95, 88, 93. then show what the outlier would do if it was added, then after removing the outlier of 59, calculate how far the other numbers are from the mean. then divide your answer by how many numbers there are to get 5. otherwise said:

(59,80,95,88,93)-59=(80+95+88+93)*/. 4=89, then 80,95,88,93=MAD= 89-80,95,88,93=(9,4, 1, 4)*/.4=4.5 ~ 5

Veronika’s five test scores are 59, 80, 95, 88, and 93. If the outlier of 59 is removed, what is the mean absolute deviation of the remaining four test scores? 4.5 5 10.8 36

Respuesta :

Otras preguntas

Veronika’s five test scores are 59, 80, 95, 88, and 93. If the outlier of 59 is removed, what is the mean absolute deviation of the remaining four test scores?
4.5
5
10.8
36