Respuesta :

caylus
Hello,

I suppose the 2th equation is 2x-3y+4=0

5x-2y=1 ........|*2        | *3
2x-3y=-4....... |*(-5)    | *-2
==> -4y+15y=2+20==>11y=22==>y=2
and 15x-4x=3+8 ==>11x=11 ==>x=1
Proof:

5*1=? 2*2+1 yes
2*1-3*2+4=? 0 yes (linear combinaison method)