Well, we need the information of the dimensions and the volume of the sweets.
Because the volume of the cylinder is
[tex] \pi r^{2}h [/tex]
r, radius, is half of the diameter, so 3/2=1.5
h is height
so the volume is
[tex] \pi r^{2} [/tex]=[tex] \pi 1.5^{2} *10[/tex]=70.65
([tex] \pi=3.14[/tex], approximately)
now, let's say that each sweet has a volume of 1, we can then fit in 70 sweets. But since you forgot to give the dimentions or volume of the sweets, all i can say is: you need to divide 70.65 by the volume of the sweets!
