Respuesta :
yo don't need max height
yo use 'find vertex' equestion
since leading term is negative, this equation has a max
the vertex is the max
in the form
y=ax^2+bx+c
vertex=-b/2a
-4x^2+24x-29
a=-4
b=24
vertex=-24/(2*-4)=-24/-8=3
max height is 3 feet
dunno wat the compete square is
I can do that fo ou though
move -29 off to side and undistriute -4
-4(x^2-6x)-29
complete the square, take 1/2 of -6 an square it andadd 0
-4(x^2-6x+9-9)-29
complete square
-4((x-3)^2-9)-29
move the 9 out by distributing the -9 to the -4
36
-4(x-3)^2+36-29
-4(x-3)^2+7
answer is 3rd option
yo use 'find vertex' equestion
since leading term is negative, this equation has a max
the vertex is the max
in the form
y=ax^2+bx+c
vertex=-b/2a
-4x^2+24x-29
a=-4
b=24
vertex=-24/(2*-4)=-24/-8=3
max height is 3 feet
dunno wat the compete square is
I can do that fo ou though
move -29 off to side and undistriute -4
-4(x^2-6x)-29
complete the square, take 1/2 of -6 an square it andadd 0
-4(x^2-6x+9-9)-29
complete square
-4((x-3)^2-9)-29
move the 9 out by distributing the -9 to the -4
36
-4(x-3)^2+36-29
-4(x-3)^2+7
answer is 3rd option
Answer: The correct answer for this question is option...
(C) −4(x − 3)2 + 7; The maximum height of the water is 7 feet.
Hope this helps :)
Have a great day!!