Respuesta :
The square of a number exceeds that number by 12. What are the two possible solutions would e B i think
x^2=x+12
minus x+12 both sides
x^2-x-12=0
factor
(x-3)(x+4)=0
set each to zero
x-3=0
x=3
x+4=0
x=-4
x=3 or -4
answer is first one
minus x+12 both sides
x^2-x-12=0
factor
(x-3)(x+4)=0
set each to zero
x-3=0
x=3
x+4=0
x=-4
x=3 or -4
answer is first one