The crop did he sells is 33.33%.
Given that
A farmer decides to sell 16 pounds of his small 48-pound potato crop.
We have to determine
What percent of the crop did he sell?
According to the question
A farmer decides to sell 16 pounds of his small 48-pound potato crop.
The percent of the crop he sells is determined by,
[tex]\rm = \dfrac{Total \ amount \ of \ crops \ he \ sells }{Total \ amount \ of \ crop}[/tex]
Then,
The percent of the crop he sells is,
[tex]\rm = \dfrac{Total \ amount \ of \ crops \ he \ sells }{Total \ amount \ of \ crop}\\\\= \dfrac{16}{48}\\\\= \dfrac{1}{3}\\\\= 0.33\\[/tex]
To convert the amount in percentage multiply by 100.
[tex]= 0.33 33\times 100\\\\= 33.33[/tex]
Hence, The crop did he sells is 33.33%.
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https://brainly.com/question/11478613
