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What is the thinnest film of a coating with n = 1.40 on glass (n=1.52) for which destructive interference of the red component (650 nm ) of an incident white light beam in air can take place by reflection?

Respuesta :

Answer:

The thinness of film is 116 nm.

Explanation:

Given that,

Wavelength = 650 nm

Refractive index = 1.40

We need to calculate the thickness

Using formula of thickness for destructive interference

[tex]2nt=(m+\dfrac{1}{2})\lambda[/tex]

Here, m = 0

[tex]2nt=\dfrac{1}{2}\lambda[/tex]

[tex]t = \dfrac{1}{4}\times\dfrac{650\times10^{-9}}{1.40}[/tex]

[tex]t=1.16\times10^{-7}\ m[/tex]

[tex]t = 116\ nm[/tex]

Hence, The thinness of film is 116 nm.