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A cylinder, with a piston pressing down with a constant pressure, is filled with 2.00 moles of a gas (n1), and its volume is 41.0 L (V1). If 0.300 mole of gas leak out, and the pressure and temperature remain the same, what is the final volume of the gas inside the cylinder?

Respuesta :

Answer:

final volume =34.85 l

Explanation:

Given data:

final Number of moles n_2 = 2.00 - 0.300 = 1.70

inital number of moles n_1 =2.00

voume v_1 = 41.0 l

from Gas law equation

PV = nRT

if P and T are constant then

[tex]\frac{v_2}{v_1} = \frac{n_2}{n_1}[/tex]

solving for v_2

[tex]V_2 = V_1 *\frac{n_2}{n_1}[/tex]

      [tex]= 41.0 *\frac{1.70}{2.00}[/tex]

         =34.85 l

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