Answer:
The thermal conductivity of the material from which the box is made is [tex]2.34\times10^{3}\ W?m^2[/tex].
Explanation:
Given that,
Inside temperature = -89.8°C = 183.2 K
Outside temperature = 18.3 °C = 291 K
Thickness of walls [tex]x=3.08\times10^{-2}[/tex]
Heat [tex]Q= 3.75\times10^{6}\ J[/tex]
Side = 0.276 m
We need to calculate the thermal conductivity of the material
Using formula of the thermal conductivity
[tex]k=\dfrac{Q\Delta x}{A(T_{2}-T_{1})}[/tex]
Put the value into the formula
[tex]k=\dfrac{3.75\times10^{6}\times3.08\times10^{-2}}{6\times(0.276^2)(291-183.2)}[/tex]
[tex]k=2344.195\ W/m^2[/tex]
[tex]k=2.34\times10^{3}\ W?m^2[/tex]
Hence, The thermal conductivity of the material from which the box is made is [tex]2.34\times10^{3}\ W?m^2[/tex].
