Answer:
Equilibrium will lie to the right.
Explanation:
[tex]K_{a}(HF)> K_{a}(C_{6}H_{5}COOH)[/tex]
That means HF is stronger acid than [tex]C_{6}H_{5}COOH[/tex].
Alternatively, it can be said that [tex]C_{6}H_{5}COO^{-}[/tex] is a stronger base than [tex]F^{-}[/tex].
Therefore HF readily gives proton to [tex]C_{6}H_{5}COO^{-}[/tex] to form [tex]C_{6}H_{5}COOH[/tex] and [tex]F^{-}[/tex] than the reverse reaction.
So, the equilibrium will lie more towards the right i.e. towards formation of [tex]C_{6}H_{5}COOH[/tex] and [tex]F^{-}[/tex].
