Answer:
Step-by-step explanation:
Males proportion [tex]p_1 = \frac{163}{532} =0.3064[/tex]
Females proportion [tex]p_2 = \frac{203}{589} =0.3447[/tex]
[tex]H_0: p_1 = p_2\\H_a: p_1 <p_2[/tex]
(one tailed test for comparison of proportions)
Test statistic = [tex]\frac{p_1-p_2}{p(1-p)\sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }[/tex]
=-1.3641
Here p= combined proportion = [tex]\frac{163+203}{532+589} \\=0.3291[/tex]
p value = 0.0869
Since p >0.05, accept null hypothesis.
The evidence does not suggest a higher proportion of females are annoyed by this behavior